%% Derivative %%

Chain Rule

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Cegep1

Mathematics

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45 words

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1 minute

Let $h(x)=(g\circ f)(x)$, then

$$h^{\prime }(x)=\frac{d}{dx}(g\circ f)(x)=g^{\prime }(f(x))\cdot f^{\prime }(x)$$

In other words, if we let $u=f(x)$,

$$\frac{dy}{dx}=\frac{dy}{du}\cdot \frac{du}{dx}$$

Proof

Proof is too hard nvm

$◻$

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Ajitani Hifumi

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