%% Derivative %%

Chain Rule

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Cegep1

Mathematics

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37 words

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1 minute

Let $h(x)=(g\circ f)(x)$, then

$$h^{\prime }(x)=\frac{d}{dx}(g\circ f)(x)=g^{\prime }(f(x))\cdot f^{\prime }(x)$$

In other words, if we let $u=f(x)$,

$$\frac{dy}{dx}=\frac{dy}{du}\cdot \frac{du}{dx}$$

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Ajitani Hifumi

Changelog

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8e28bb0-Vault update: 2024-10-10T01:00:24

b6f0df6-Vault update: 2024-10-09T08:30:52